Simplifying Algebraic Expressions: 6d-2(d-2) and 3(d-12)
In algebra, simplifying expressions is an essential skill to master. It involves combining like terms and eliminating any parentheses or other grouping symbols. In this article, we will simplify two algebraic expressions: 6d-2(d-2) and 3(d-12).
Simplifying 6d-2(d-2)
Let's start with the first expression: 6d-2(d-2). To simplify this expression, we need to follow the order of operations (PEMDAS):
- Evaluate the expression inside the parentheses: d-2 = ?
We don't have a value for d, so we'll leave it as d-2.
- Multiply 2 with the expression inside the parentheses: 2(d-2) = 2d - 4
Now, rewrite the original expression with the simplified parentheses:
6d - 2d + 4
Combine like terms:
- Combine the d terms: 6d - 2d = 4d
- The constant term is 4
So, the simplified expression is:
4d + 4
Simplifying 3(d-12)
Now, let's simplify the second expression: 3(d-12). Again, we'll follow the order of operations:
- Evaluate the expression inside the parentheses: d-12 = ?
We don't have a value for d, so we'll leave it as d-12.
- Multiply 3 with the expression inside the parentheses: 3(d-12) = 3d - 36
That's it! We've simplified the expression. There are no like terms to combine.
So, the simplified expression is:
3d - 36
In conclusion, simplifying algebraic expressions involves following the order of operations and combining like terms. By doing so, we can simplify complex expressions into more manageable forms. In this article, we simplified 6d-2(d-2) to 4d + 4 and 3(d-12) to 3d - 36.
