5^(x)=(0.5)^(y)=1000 Then The Value Of (1)/(x)-(1)/(y) Is

2 min read Jul 27, 2024
5^(x)=(0.5)^(y)=1000 Then The Value Of (1)/(x)-(1)/(y) Is

Solving the Equation: 5^(x) = (0.5)^(y) = 1000

In this problem, we are given the equation 5^(x) = (0.5)^(y) = 1000, and we need to find the value of (1)/(x) - (1)/(y).

Step 1: Simplify the Equation

First, let's simplify the equation by rewriting 0.5 as 1/2:

5^(x) = (1/2)^(y) = 1000

Step 2: Convert to Exponential Form

Next, we can convert the equation to exponential form by taking the logarithm base 10 of both sides:

log(5^(x)) = log((1/2)^(y)) = log(1000)

Using the property of logarithms, we can rewrite the equation as:

x log(5) = y log(1/2) = 3 log(10)

Step 3: Solve for x and y

Now, we can solve for x and y separately:

x log(5) = 3 log(10) x = 3 log(10) / log(5)

y log(1/2) = 3 log(10) y = 3 log(10) / log(1/2)

Using the property of logarithms, we can simplify x and y further:

x = 3 / log(5) / log(2) y = 3 / log(1/2) / log(2)

Step 4: Find the Value of (1)/(x) - (1)/(y)

Now that we have expressions for x and y, we can find the value of (1)/(x) - (1)/(y):

(1)/(x) - (1)/(y) = log(2) / 3 - log(2) / 3 = 0

Therefore, the value of (1)/(x) - (1)/(y) is 0.

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