(x + 2)² + (y + 1)² = 13: Solving the Equation
In this article, we will solve the equation (x + 2)² + (y + 1)² = 13.
Expanding the Equation
First, let's expand the equation by applying the exponent rule:
(x + 2)² = x² + 4x + 4 (y + 1)² = y² + 2y + 1
Now, substitute these expressions into the original equation:
x² + 4x + 4 + y² + 2y + 1 = 13
Simplifying the Equation
Combine like terms:
x² + y² + 4x + 2y - 8 = 0
Rearranging the Terms
Rearrange the terms to form a quadratic equation in x and y:
x² + y² + 4x + 2y - 8 = 0
Unfortunately, this equation does not have a simple solution. However, we can try to find the possible values of x and y by plotting the equation on a graph.
Graphical Representation
The equation x² + y² + 4x + 2y - 8 = 0 represents a circle with a center at (-2, -1) and a radius of √13.
Conclusion
In conclusion, the equation (x + 2)² + (y + 1)² = 13 does not have a simple algebraic solution. However, we can represent the equation graphically as a circle.