A Rectangle Has A Height Of 7a^2 And A Width Of A^4+5a^2+4

less than a minute read Aug 29, 2024
A Rectangle Has A Height Of 7a^2 And A Width Of A^4+5a^2+4

Finding the Area of a Rectangle with Given Dimensions

We are given a rectangle with a height of 7a<sup>2</sup> and a width of a<sup>4</sup> + 5a<sup>2</sup> + 4. To find the area of the rectangle, we can use the formula:

Area = Height x Width

Let's substitute the given values:

Area = (7a<sup>2</sup>) x (a<sup>4</sup> + 5a<sup>2</sup> + 4)

Now, we can simplify the expression by distributing the 7a<sup>2</sup>:

Area = 7a<sup>2</sup> * a<sup>4</sup> + 7a<sup>2</sup> * 5a<sup>2</sup> + 7a<sup>2</sup> * 4

Area = 7a<sup>6</sup> + 35a<sup>4</sup> + 28a<sup>2</sup>

Therefore, the area of the rectangle is 7a<sup>6</sup> + 35a<sup>4</sup> + 28a<sup>2</sup>.