6 X Squared Space Plus Space 13x Space Minus Space 63

3 min read Jul 27, 2024
6 X Squared Space Plus Space 13x Space Minus Space 63

6x² + 13x - 63: Understanding Quadratic Expressions

In algebra, quadratic expressions are a fundamental concept that helps us solve a wide range of problems. One such expression is 6x² + 13x - 63. In this article, we will break down this expression, understand its components, and explore its properties.

What is a Quadratic Expression?

A quadratic expression is a polynomial expression of degree two, meaning the highest power of the variable (in this case, x) is two. It has the general form:

ax² + bx + c

where a, b, and c are constants, and x is the variable.

Breaking Down 6x² + 13x - 63

Let's analyze the given expression:

6x² + 13x - 63

Here, we can identify the components:

  • a = 6: The coefficient of the x² term.
  • b = 13: The coefficient of the x term.
  • c = -63: The constant term.

Properties of 6x² + 13x - 63

Factoring

Factorization is a process of expressing an algebraic expression as a product of simpler expressions. Unfortunately, 6x² + 13x - 63 does not have any obvious factors. However, we can try to factor it using various techniques, such as the ac method or the quadratic formula.

Graphing

The graph of 6x² + 13x - 63 is a parabola that opens upwards. The x-intercepts can be found by setting the expression equal to zero and solving for x. The y-intercept is the constant term, -63.

Solving

To solve the equation 6x² + 13x - 63 = 0, we need to find the values of x that make the expression equal to zero. We can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

In this case, a = 6, b = 13, and c = -63. Plugging in these values, we get:

x = (-13 ± √(13² - 4(6)(-63))) / 2(6)

Simplifying the expression, we get two possible values for x.

Conclusion

In conclusion, 6x² + 13x - 63 is a quadratic expression that can be analyzed and solved using various algebraic techniques. By understanding its components, properties, and behavior, we can gain insights into the underlying structure of the expression and apply it to real-world problems.

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