1 2 3 4 5 6 Pattern In Python

4 min read Jun 07, 2024

1 2 3 4 5 6 Pattern in Python

The 1 2 3 4 5 6 pattern is a popular problem in programming, where you need to print a sequence of numbers in a specific pattern. In this article, we will explore how to implement the 1 2 3 4 5 6 pattern in Python.

What is the 1 2 3 4 5 6 Pattern?

The 1 2 3 4 5 6 pattern is a sequence of numbers that increases by 1, then 2, then 3, and so on. The pattern looks like this:

1
2 3
4 5 6
7 8 9 10
11 12 13 14 15

As you can see, each row has one more number than the previous row, and the numbers increase sequentially.

Implementation in Python

To implement the 1 2 3 4 5 6 pattern in Python, we can use a simple loop to generate the sequence. Here's an example code:

n = 5  # number of rows
num = 1
for i in range(n):
    for j in range(i + 1):
        print(num, end=' ')
        num += 1
    print()

Let's break down the code:

We define the number of rows n and the starting number num.
We use a nested loop to generate the sequence. The outer loop i runs from 0 to n-1, and the inner loop j runs from 0 to i.
Inside the inner loop, we print the current number num followed by a space, and then increment num by 1.
After each inner loop iteration, we print a newline character to move to the next row.

Output

Running the code above will produce the following output:

1 
2 3 
4 5 6 
7 8 9 10 
11 12 13 14 15

Which is the desired 1 2 3 4 5 6 pattern!

Conclusion

The 1 2 3 4 5 6 pattern is a fun and challenging problem in programming. With Python's simplicity and flexibility, we can easily implement this pattern using a nested loop. By understanding the logic behind the pattern, you can apply this concept to other programming problems and create more complex sequences.

1 2 3 4 5 6 Pattern In Python