0 6(x-2)+4 6=0 4(7+x)

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Jun 03, 2024

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Solving Linear Equations: 0 = 6(x-2)+4 and 4(7+x) = 6

In this article, we will explore two linear equations: 0 = 6(x-2)+4 and 4(7+x) = 6. We will learn how to solve these equations and find the value of x.

Equation 1: 0 = 6(x-2)+4

To solve this equation, we can start by isolating the term with the variable x.

0 = 6(x-2)+4

Subtract 4 from both sides of the equation:

-4 = 6(x-2)

Divide both sides of the equation by -6:

(x-2) = -4/6

Add 2 to both sides of the equation:

x = -4/6 + 2

x = (-4+12)/6

x = 8/6

x = 4/3

Therefore, the value of x is 4/3.

Equation 2: 4(7+x) = 6

To solve this equation, we can start by distributing the 4 to the terms inside the parentheses:

28 + 4x = 6

Subtract 28 from both sides of the equation:

4x = -22

Divide both sides of the equation by 4:

x = -22/4

x = -11/2

Therefore, the value of x is -11/2.

Conclusion

In this article, we have learned how to solve two linear equations: 0 = 6(x-2)+4 and 4(7+x) = 6. By isolating the variable x and using basic algebraic operations, we found that the value of x is 4/3 for the first equation and -11/2 for the second equation.