(iii) ( Sqrt 10^ 2 Frac 1 2 Log (16) = )

2 min read Jun 12, 2024
(iii) ( Sqrt 10^ 2 Frac 1 2 Log (16) = )

Simplifying the Expression: $(\sqrt{10^2}) \frac{1}{2} \log (16)$

In this article, we will simplify the given expression: $(\sqrt{10^2}) \frac{1}{2} \log (16)$. Let's break it down step by step.

Step 1: Simplify the Square Root The first part of the expression is $(\sqrt{10^2})$. To simplify this, we can use the property of exponents that states: $\sqrt{x^2} = x$. Therefore, we can simplify $(\sqrt{10^2})$ to:

$(\sqrt{10^2}) = 10$

Step 2: Evaluate the Logarithm The next part of the expression is $\log (16)$. To evaluate this, we need to find the power to which the base must be raised to equal 16. Since 16 is a power of 2 (i.e., $2^4 = 16$), we can write:

$\log (16) = \log (2^4) = 4 \log (2)$

Step 3: Simplify the Fraction Now, we have the expression: $10 \cdot \frac{1}{2} \cdot 4 \log (2)$. To simplify this fraction, we can multiply the numerator by the denominator:

$10 \cdot \frac{1}{2} \cdot 4 \log (2) = 20 \log (2)$

Therefore, the simplified expression is:

$(\sqrt{10^2}) \frac{1}{2} \log (16) = 20 \log (2)$

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