A Sphere of Radius 0.03 m is Suspended
This statement sets the stage for a physics problem, likely involving forces, equilibrium, or perhaps even fluid dynamics. To understand the situation better, we need more context. Here are some questions we should ask to gain clarity:
1. What is the sphere made of?
Knowing the material of the sphere is crucial for determining its density, which plays a significant role in calculating forces like gravity and buoyancy.
2. How is the sphere suspended?
- Is it hanging from a string? This would introduce tension force.
- Is it floating in a fluid? This would involve buoyancy.
- Is it being held by a magnet? This would involve magnetic force.
3. What is the surrounding environment?
- Is it in air? This would involve air resistance.
- Is it in water? This would involve water resistance.
- Is it in a vacuum? This simplifies the scenario by eliminating air resistance.
4. What is the problem asking for?
- What is the weight of the sphere?
- What is the tension in the string?
- What is the buoyant force acting on the sphere?
- What is the net force on the sphere?
Once we have answers to these questions, we can apply relevant physics principles to analyze the situation and solve the problem.
Example:
Let's say the sphere is made of iron (density 7874 kg/m³) and is suspended by a string in air. We want to calculate the tension in the string.
Solution:
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Calculate the volume of the sphere:
- V = (4/3)πr³ = (4/3)π(0.03 m)³ ≈ 1.13 x 10⁻⁴ m³
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Calculate the mass of the sphere:
- m = ρV = (7874 kg/m³)(1.13 x 10⁻⁴ m³) ≈ 0.89 kg
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Calculate the weight of the sphere:
- W = mg = (0.89 kg)(9.8 m/s²) ≈ 8.72 N
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Since the sphere is in equilibrium, the tension in the string must equal the weight of the sphere.
- Therefore, the tension in the string is approximately 8.72 N.
Remember: This is just one example. The specific solution will depend on the context of the problem.
