5^(x-1)=10^(x)*2^(-x)*5^(x+1)

2 min read Jul 27, 2024
5^(x-1)=10^(x)*2^(-x)*5^(x+1)

Solving the Equation: 5^(x-1) = 10^(x) * 2^(-x) * 5^(x+1)

In this article, we will solve the equation 5^(x-1) = 10^(x) * 2^(-x) * 5^(x+1) and find the value of x.

Step 1: Simplify the Right-Hand Side of the Equation

First, let's simplify the right-hand side of the equation:

10^(x) = (2 * 5)^x = 2^x * 5^x

So, the equation becomes:

5^(x-1) = 2^x * 5^x * 2^(-x) * 5^(x+1)

Step 2: Combine the Exponents

Next, let's combine the exponents of the 2 and 5:

5^(x-1) = 2^(x-x) * 5^(x+x+1) 5^(x-1) = 2^0 * 5^(2x+1) 5^(x-1) = 1 * 5^(2x+1) 5^(x-1) = 5^(2x+1)

Step 3: Equate the Exponents

Now, we can equate the exponents:

x - 1 = 2x + 1

Step 4: Solve for x

Subtract 2x from both sides:

-x - 1 = 1

Add 1 to both sides:

-x = 2

Multiply both sides by -1:

x = -2

Conclusion

The value of x that satisfies the equation 5^(x-1) = 10^(x) * 2^(-x) * 5^(x+1) is x = -2.

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