3sin^(-1)(2x)/(1+x^(2))-4cos^(-1)(1-x^(2))/(1+x^(2))+2tan^(-1)(2x)/(1-x^(2))=(pi)/(3)

5 min read Jul 25, 2024
3sin^(-1)(2x)/(1+x^(2))-4cos^(-1)(1-x^(2))/(1+x^(2))+2tan^(-1)(2x)/(1-x^(2))=(pi)/(3)

Solving the Inverse Trigonometric Equation

Equation: 3sin^(-1)(2x)/(1+x^(2)) - 4cos^(-1)(1-x^(2))/(1+x^(2)) + 2tan^(-1)(2x)/(1-x^(2)) = (pi)/(3)

In this article, we will solve the given inverse trigonometric equation and find the value of x.

Step 1: Simplify the Equation

Let's start by simplifying the given equation. We can do this by using the properties of inverse trigonometric functions.

Recall that:

  • sin^(-1)(x) + cos^(-1)(x) = (pi)/(2)
  • tan^(-1)(x) = sin^(-1)(x/√(1+x^(2)))

Using these properties, we can rewrite the given equation as:

3sin^(-1)(2x)/(1+x^(2)) - 4((pi)/(2) - sin^(-1)(x))/(1+x^(2)) + 2sin^(-1)(2x/√(1+x^(2)))/(1-x^(2)) = (pi)/(3)

Step 2: Simplify Further

Now, let's simplify the equation further by combining the terms.

3sin^(-1)(2x)/(1+x^(2)) - 2pi/(1+x^(2)) + 4sin^(-1)(x)/(1+x^(2)) + 2sin^(-1)(2x/√(1+x^(2)))/(1-x^(2)) = (pi)/(3)

Step 3: Find the Common Denominator

Next, let's find the common denominator of the terms.

The common denominator is (1+x^(2))(1-x^(2)).

Now, we can rewrite the equation as:

(3sin^(-1)(2x) - 2pi + 4sin^(-1)(x) + 2(1+x^(2))sin^(-1)(2x/√(1+x^(2))))/(1-x^(4)) = (pi)/(3)

Step 4: Solve for x

Now, we can solve for x.

Let's assume sin^(-1)(2x) = A, sin^(-1)(x) = B, and sin^(-1)(2x/√(1+x^(2))) = C.

Then, the equation becomes:

(3A - 2pi + 4B + 2(1+x^(2))C)/(1-x^(4)) = (pi)/(3)

Simplifying further, we get:

3A + 4B + 2(1+x^(2))C = pi/3 + 2pi(1-x^(4))/3

Now, we can equate the coefficients of A, B, and C.

This gives us:

A = pi/9, B = pi/12, and C = pi/18

Step 5: Find the Value of x

Now, we can find the value of x.

From A = pi/9, we get:

sin^(-1)(2x) = pi/9

sin(2x) = sin(pi/9)

2x = pi/9 or 2x = 2pi - pi/9

x = pi/18 or x = pi/2 - pi/18

x = pi/18 or x = 4pi/9

From B = pi/12, we get:

sin^(-1)(x) = pi/12

sin(x) = sin(pi/12)

x = pi/12 or x = 2pi - pi/12

x = pi/12 or x = 11pi/12

From C = pi/18, we get:

sin^(-1)(2x/√(1+x^(2))) = pi/18

sin(2x/√(1+x^(2))) = sin(pi/18)

2x/√(1+x^(2)) = pi/18 or 2x/√(1+x^(2)) = 2pi - pi/18

x = pi/36(1+x^(2)) or x = (2pi - pi/18)√(1+x^(2))/2

Simplifying further, we get:

x = pi/36(1+x^(2)) or x = (8pi - pi/9)√(1+x^(2))/18

Conclusion

Therefore, the value of x is:

x = pi/18 or x = 4pi/9 or x = pi/12 or x = 11pi/12 or x = pi/36(1+x^(2)) or x = (8pi - pi/9)√(

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