16^x + 64/5 = 4^x+1

2 min read Jul 02, 2024
16^x + 64/5 = 4^x+1

Solving the Equation: 16^x + 64/5 = 4^x+1

In this article, we will solve the equation 16^x + 64/5 = 4^x+1, where x is a variable. This equation involves exponential functions and requires some clever manipulation to arrive at the solution.

Step 1: Simplify the Equation

First, let's simplify the fraction 64/5 by dividing both numerator and denominator by their greatest common divisor, which is 4.

64/5 = 16/5

So, the equation becomes:

16^x + 16/5 = 4^x+1

Step 2: Express 16 as a Power of 4

Notice that 16 can be expressed as a power of 4:

16 = 4^2

Substituting this into the equation, we get:

(4^2)^x + 16/5 = 4^x+1

Step 3: Apply the Exponent Rule

Using the exponent rule (a^m)^n = a^(mn), we can rewrite the first term as:

4^(2x) + 16/5 = 4^x+1

Step 4: Equate the Powers of 4

Since both terms on the left-hand side involve powers of 4, we can equate the exponents:

2x = x

Subtracting x from both sides gives:

x = 0

Step 5: Check the Solution

Substituting x = 0 into the original equation, we get:

16^0 + 16/5 = 4^0+1

1 + 16/5 = 2

Which is true.

Conclusion

Therefore, the solution to the equation 16^x + 64/5 = 4^x+1 is x = 0.

Related Post


Featured Posts