1-4 Cos^2(x-5pi/12)=

3 min read Jun 15, 2024
1-4 Cos^2(x-5pi/12)=

Trigonometry: Evaluating the Expression 1 - 4cos^2(x - 5π/12)

In this article, we will evaluate the trigonometric expression 1 - 4cos^2(x - 5π/12). To do this, we will use the properties of trigonometric functions and algebraic manipulations.

Step 1: Simplify the Expression

First, let's rewrite the expression by using the cosine identity:

cos(A - B) = cos(A)cos(B) + sin(A)sin(B)

In our case, A = x and B = 5π/12. Then:

cos(x - 5π/12) = cos(x)cos(5π/12) + sin(x)sin(5π/12)

Now, we can rewrite the original expression as:

1 - 4(cos(x)cos(5π/12) + sin(x)sin(5π/12))^2

Step 2: Expand the Squared Term

Using the binomial theorem, we expand the squared term:

(cos(x)cos(5π/12) + sin(x)sin(5π/12))^2 = cos^2(x)cos^2(5π/12) + 2cos(x)sin(x)cos(5π/12)sin(5π/12) + sin^2(x)sin^2(5π/12)

Now, we can rewrite the expression as:

1 - 4(cos^2(x)cos^2(5π/12) + 2cos(x)sin(x)cos(5π/12)sin(5π/12) + sin^2(x)sin^2(5π/12))

Step 3: Simplify the Expression

Using the Pythagorean identity sin^2(x) + cos^2(x) = 1, we can simplify the expression:

1 - 4(cos^2(x)cos^2(5π/12) + 2cos(x)sin(x)cos(5π/12)sin(5π/12) + (1 - cos^2(x))sin^2(5π/12))

Now, we can combine like terms:

= 1 - 4cos^2(x)cos^2(5π/12) - 8cos(x)sin(x)cos(5π/12)sin(5π/12) + 4sin^2(x)sin^2(5π/12)

Final Result

The final result is a simplified expression:

1 - 4cos^2(x - 5π/12) = 4sin^2(x)sin^2(5π/12) - 8cos(x)sin(x)cos(5π/12)sin(5π/12) - 4cos^2(x)cos^2(5π/12) + 1

This expression has been simplified using trigonometric identities and algebraic manipulations.