1/x-2/y+4=0 1/y-1/z+1=0 2/x+3/x=14

3 min read Jun 16, 2024
1/x-2/y+4=0 1/y-1/z+1=0 2/x+3/x=14

System of Linear Equations

In this article, we will discuss a system of linear equations and how to solve it.

The Equations

We are given three linear equations:

Equation 1

1/x - 2/y + 4 = 0

Equation 2

1/y - 1/z + 1 = 0

Equation 3

2/x + 3/x = 14

Solving the System

To solve this system of linear equations, we can start by simplifying each equation.

Simplifying Equation 1

1/x - 2/y + 4 = 0

We can rewrite this equation as:

1/x = 2/y - 4

Simplifying Equation 2

1/y - 1/z + 1 = 0

We can rewrite this equation as:

1/y = 1/z - 1

Simplifying Equation 3

2/x + 3/x = 14

We can rewrite this equation as:

5/x = 14

Solving for x Now that we have simplified each equation, we can start solving for x.

From Equation 3, we know that:

5/x = 14

Multiplying both sides by x, we get:

5 = 14x

Dividing both sides by 14, we get:

x = 5/14

Solving for y Now that we have found x, we can substitute this value into Equation 1 to solve for y.

From Equation 1, we know that:

1/x = 2/y - 4

Substituting x = 5/14, we get:

1/(5/14) = 2/y - 4

Simplifying this equation, we get:

y = 1/2

Solving for z Now that we have found y, we can substitute this value into Equation 2 to solve for z.

From Equation 2, we know that:

1/y = 1/z - 1

Substituting y = 1/2, we get:

1/(1/2) = 1/z - 1

Simplifying this equation, we get:

z = 2/3

Conclusion In conclusion, we have solved the system of linear equations and found the values of x, y, and z to be:

x = 5/14 y = 1/2 z = 2/3

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