Dilution of 0.1 M HCl by 100 Times
In this article, we will discuss the process of diluting 0.1 M hydrochloric acid (HCl) by 100 times and calculate the resulting concentration of the diluted solution.
Initial Concentration and Volume
The initial concentration of the HCl solution is 0.1 M, which means it contains 0.1 moles of HCl per liter of solution. Let's assume we have 100 mL (0.1 L) of this solution.
Dilution by 100 Times
To dilute the solution by 100 times, we need to add a sufficient amount of water to the initial solution to achieve a total volume of 10 L (100 times 0.1 L).
Calculation of Resulting Concentration
To calculate the resulting concentration of the diluted solution, we can use the following formula:
M1V1 = M2V2
where: M1 = initial concentration (0.1 M) V1 = initial volume (0.1 L) M2 = resulting concentration (unknown) V2 = resulting volume (10 L)
Rearranging the formula to solve for M2, we get:
M2 = M1V1 / V2 = (0.1 M) × (0.1 L) / 10 L = 0.001 M
Resulting Concentration
The resulting concentration of the diluted HCl solution is 0.001 M.
Conclusion
In this article, we successfully diluted 0.1 M HCl solution by 100 times, achieving a resulting concentration of 0.001 M. This process is commonly used in laboratory settings to prepare solutions of specific concentrations for various experiments and reactions.
