%3D0-5(7-3y)-1-9.jpeg "0 4(6-4y)=0 5(7-3y)-1 9")
Solving the Equation: 0 = 4(6-4y) = 5(7-3y)-1 = 9
In this article, we will explore how to solve a system of linear equations involving three equations. The equations are:
Equation 1: 0 = 4(6-4y) Equation 2: 5(7-3y) - 1 = 9 Equation 3: (no equation given, assuming it's not relevant to the problem)
Let's break down each equation and solve for y.
Solving Equation 1: 0 = 4(6-4y)
To solve for y, we can start by distributing the 4 to the terms inside the parentheses:
0 = 24 - 16y
Next, we can add 16y to both sides of the equation to get:
16y = 24
Dividing both sides by 16, we get:
y = 24/16 y = 1.5
Solving Equation 2: 5(7-3y) - 1 = 9
Let's start by distributing the 5 to the terms inside the parentheses:
35 - 15y - 1 = 9
Adding 1 to both sides gives:
35 - 15y = 10
Subtracting 35 from both sides gives:
-15y = -25
Dividing both sides by -15, we get:
y = 25/15 y = 1.67
Comparing Solutions
We have found two different values of y: 1.5 and 1.67. This suggests that there may be an inconsistency in the equations, and there is no single value of y that satisfies all three equations simultaneously.
In conclusion, we have solved for y in each equation, but the solutions do not match, indicating an inconsistency in the system of equations.
