0 3(x-2)=0 6+0 2(x+4)

3 min read Jul 02, 2024

Solving Linear Equations: 0 = 3(x-2) and 0 = 2(x+4)

In this article, we will explore how to solve two simple linear equations: 0 = 3(x-2) and 0 = 2(x+4). We will use basic algebraic techniques to find the values of x that satisfy these equations.

Equation 1: 0 = 3(x-2)

The equation 0 = 3(x-2) can be solved by following these steps:

Step 1: Distribute the 3 to the terms inside the parentheses

0 = 3x - 6

Step 2: Add 6 to both sides of the equation

6 = 3x

Step 3: Divide both sides of the equation by 3

x = 6/3 x = 2

Therefore, the value of x that satisfies the equation 0 = 3(x-2) is x = 2.

Equation 2: 0 = 2(x+4)

The equation 0 = 2(x+4) can be solved by following these steps:

Step 1: Distribute the 2 to the terms inside the parentheses

0 = 2x + 8

Step 2: Subtract 8 from both sides of the equation

-8 = 2x

Step 3: Divide both sides of the equation by 2

x = -8/2 x = -4

Therefore, the value of x that satisfies the equation 0 = 2(x+4) is x = -4.

Conclusion

In this article, we have solved two simple linear equations: 0 = 3(x-2) and 0 = 2(x+4). We found that the values of x that satisfy these equations are x = 2 and x = -4, respectively. These solutions can be used to solve various problems in mathematics, physics, and other fields.