%3D0-3(2y-1)-0-9.jpeg "0 2(5y-2)=0 3(2y-1)-0 9")
Solving the Equation: 0.2(5y-2) = 0 and 3(2y-1) - 0.9
In this article, we will explore how to solve two equations: 0.2(5y-2) = 0 and 3(2y-1) - 0.9. These equations may seem complex at first, but with some basic algebraic manipulations, we can solve for the variable y.
Equation 1: 0.2(5y-2) = 0
To solve this equation, we can start by distributing the 0.2 to the terms inside the parentheses:
0.2(5y) - 0.2(2) = 0 1y - 0.4 = 0
Now, let's add 0.4 to both sides of the equation to get:
1y = 0.4
Dividing both sides by 1, we get:
y = 0.4
So, the solution to the first equation is y = 0.4.
Equation 2: 3(2y-1) - 0.9
To solve this equation, we can start by distributing the 3 to the terms inside the parentheses:
6y - 3 - 0.9 = 0
Now, let's add 3 and 0.9 to both sides of the equation to get:
6y = 3.9
Dividing both sides by 6, we get:
y = 3.9/6 y = 0.65
So, the solution to the second equation is y = 0.65.
Conclusion
In this article, we solved two equations: 0.2(5y-2) = 0 and 3(2y-1) - 0.9. The solutions to these equations are y = 0.4 and y = 0.65, respectively. By applying basic algebraic manipulations, we were able to solve for the variable y in both equations.
