(x/3+1/x)^5 Binomial Expansion

3 min read Jun 07, 2024
(x/3+1/x)^5 Binomial Expansion

Binomial Expansion of (x/3+1/x)^5

Introduction

In algebra, binomial expansion is a fundamental concept used to expand powers of a binomial expression. In this article, we will explore the binomial expansion of (x/3+1/x)^5.

The Binomial Theorem

The binomial theorem is a mathematical formula that describes the expansion of powers of a binomial expression. It is stated as follows:

$(a+b)^n = \sum_{k=0}^n \binom{n}{k} a^{n-k} b^k$

where $a$ and $b$ are real numbers, $n$ is a positive integer, and $\binom{n}{k}$ is the binomial coefficient.

Expanding (x/3+1/x)^5

Using the binomial theorem, we can expand (x/3+1/x)^5 as follows:

$(x/3+1/x)^5 = \sum_{k=0}^5 \binom{5}{k} (x/3)^{5-k} (1/x)^k$

Simplifying the expression, we get:

$(x/3+1/x)^5 = \binom{5}{0} (x/3)^5 + \binom{5}{1} (x/3)^4 (1/x) + \binom{5}{2} (x/3)^3 (1/x)^2 + \binom{5}{3} (x/3)^2 (1/x)^3 + \binom{5}{4} (x/3) (1/x)^4 + \binom{5}{5} (1/x)^5$

Simplifying the Terms

Simplifying each term, we get:

$= \frac{x^5}{243} + 5\frac{x^4}{81} + 10\frac{x^3}{27} + 10\frac{x^2}{9} + 5\frac{x}{3} + 1$

Conclusion

In this article, we have successfully expanded (x/3+1/x)^5 using the binomial theorem. The result is a polynomial expression with terms in increasing powers of x. Understanding binomial expansion is crucial in algebra and has numerous applications in mathematics, physics, and engineering.

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