(d^2+1)y=sinx

4 min read Jul 03, 2024
(d^2+1)y=sinx

Linear Differential Equations: Solving (d^2+1)y=sinx

In this article, we will explore the solution to the linear differential equation (d^2+1)y=sinx. This equation is a classic example of a second-order linear ordinary differential equation (ODE) with a sinusoidal forcing term.

The Equation

The equation is given by:

(d^2+1)y = sinx

where y is the dependent variable, x is the independent variable, and d is the differential operator.

Homogeneous Solution

To solve this equation, we first need to find the homogeneous solution, which is the solution to the equation when the right-hand side is zero. In this case, the homogeneous equation is:

(d^2+1)y = 0

To solve this equation, we can use the characteristic equation, which is:

r^2 + 1 = 0

This equation has two complex roots:

r = ±i

Using these roots, we can write the homogeneous solution as:

y_h = c1cosx + c2sinx

where c1 and c2 are constants.

Particular Solution

To find the particular solution, we need to find a function y_p that satisfies the original equation:

(d^2+1)y_p = sinx

Using the method of undetermined coefficients, we assume that the particular solution has the form:

y_p = Acosx + Bsinx

Substituting this into the original equation, we get:

(-Acosx - Bsinx) + (Acosx + Bsinx) = sinx

Simplifying this equation, we get:

-Acosx + Bsinx = sinx

Equating the coefficients of cosx and sinx, we get:

A = 0 B = 1/2

Therefore, the particular solution is:

y_p = (1/2)sinx

General Solution

The general solution to the equation is the sum of the homogeneous solution and the particular solution:

y = y_h + y_p = c1cosx + c2sinx + (1/2)sinx

Simplifying this equation, we get:

y = c1cosx + (c2 + 1/2)sinx

This is the general solution to the linear differential equation (d^2+1)y=sinx.

Conclusion

In this article, we have solved the linear differential equation (d^2+1)y=sinx using the method of undetermined coefficients. The general solution to the equation is a linear combination of cosx and sinx. This equation is an important example of a second-order linear ODE with a sinusoidal forcing term, and its solution has many applications in physics, engineering, and other fields.

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