((5^(-1)times 7^(2))/(5^(2)times 7^(-4)))^(7/2)times((5^(-2)times 7^(3))/(5^(3)times7^(-5)))^(-5/2)

2 min read Jun 07, 2024
((5^(-1)times 7^(2))/(5^(2)times 7^(-4)))^(7/2)times((5^(-2)times 7^(3))/(5^(3)times7^(-5)))^(-5/2)

Simplifying the Given Expression

The given expression is:

$\left(\frac{5^{-1} \times 7^{2}}{5^{2} \times 7^{-4}}\right)^{7/2} \times \left(\frac{5^{-2} \times 7^{3}}{5^{3} \times 7^{-5}}\right)^{-5/2}$

To simplify this expression, we can start by simplifying each fraction separately.

Simplifying the First Fraction

$\frac{5^{-1} \times 7^{2}}{5^{2} \times 7^{-4}} = \frac{7^{2}}{5^{3} \times 7^{-4}} = \frac{7^{2}}{5^{3}} \times 7^{4} = \frac{1}{5^{3}} \times 7^{6} = \frac{7^{6}}{5^{3}}$

Simplifying the Second Fraction

$\frac{5^{-2} \times 7^{3}}{5^{3} \times 7^{-5}} = \frac{7^{3}}{5^{5} \times 7^{-5}} = \frac{7^{3}}{5^{5}} \times 7^{5} = \frac{7^{8}}{5^{5}}$

Simplifying the Entire Expression

Now, we can simplify the entire expression:

$\left(\frac{7^{6}}{5^{3}}\right)^{7/2} \times \left(\frac{7^{8}}{5^{5}}\right)^{-5/2}$

Using the rule of exponents, we can simplify further:

$\left(\frac{7^{6}}{5^{3}}\right)^{7/2} = \frac{7^{21}}{5^{21/2}}$

$\left(\frac{7^{8}}{5^{5}}\right)^{-5/2} = \frac{5^{25/2}}{7^{20}}$

Final Simplification

Now, we can multiply the two expressions:

$\frac{7^{21}}{5^{21/2}} \times \frac{5^{25/2}}{7^{20}} = \frac{7^{1}}{5^{-2}} = 5^{2} \times 7$

Therefore, the simplified expression is:

$\boxed{25 \times 7 = 175}$

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